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Given the address 192.168.20.19/28, which of the following are valid host addresses on this subnet? (Choose two)
What are the two types of subnetting?
Which of the following host addresses are members of networks that can be routed across the public Internet? (Choose three)
A – 10.172.13.65
B – 172.16.223.125
C – 188.8.131.52
D – 192.168.23.252
E – 184.108.40.206
F – 220.127.116.11
How many subnets can be gained by subnetting 172.17.32.0/23 into a /27 mask, and how many usable host addresses will there be per subnet?
A. 8 subnets, 31 hosts
B. 8 subnets, 32 hosts
C. 16 subnets, 30 hosts
D. 16 subnets, 32 hosts
E. A Class B address cant be subnetted into the fourth octet.
Using the illustration from the previous question, what would be the IP address of S0 if you were using the first subnet? The network ID is 192.168.10.0/28 and you need to use the last available IP address in the range. Again, the zero subnet should not be considered valid for this question.
A. 192.168.10.24 B. 192.168.10.62
C. 192.168.10.30 D. 192.168.10.127
Which two statements describe the IP address 10.16.3.65/23?
The subnet address is 10.16.3.0 255.255.254.0.
The lowest host address in the subnet is 10.16.2.1 255.255.254.0.
The last valid host address in the subnet is 10.16.2.254 255.255.254.0.
The broadcast address of the subnet is 10.16.3.255 255.255.254.0.
A. 1 and 3
B. 2 and 4
C. 1, 2 and 4
D. 2, 3 and 4